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4.9t^2+9.8t=39.2
We move all terms to the left:
4.9t^2+9.8t-(39.2)=0
We add all the numbers together, and all the variables
4.9t^2+9.8t-39.2=0
a = 4.9; b = 9.8; c = -39.2;
Δ = b2-4ac
Δ = 9.82-4·4.9·(-39.2)
Δ = 864.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.8)-\sqrt{864.36}}{2*4.9}=\frac{-9.8-\sqrt{864.36}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.8)+\sqrt{864.36}}{2*4.9}=\frac{-9.8+\sqrt{864.36}}{9.8} $
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